3(x+2)=2[x-(1-x)]

Solution for 3(x+2)=2[x-(1-x)] equation:

Simplifying
3(x + 2) = 2[x + -1(1 + -1x)]

Reorder the terms:
3(2 + x) = 2[x + -1(1 + -1x)]
(2 * 3 + x * 3) = 2[x + -1(1 + -1x)]
(6 + 3x) = 2[x + -1(1 + -1x)]
6 + 3x = 2[x + (1 * -1 + -1x * -1)]
6 + 3x = 2[x + (-1 + 1x)]

Reorder the terms:
6 + 3x = 2[-1 + x + 1x]

Combine like terms: x + 1x = 2x
6 + 3x = 2[-1 + 2x]
6 + 3x = [-1 * 2 + 2x * 2]
6 + 3x = [-2 + 4x]

Solving
6 + 3x = -2 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.
6 + 3x + -4x = -2 + 4x + -4x

Combine like terms: 3x + -4x = -1x
6 + -1x = -2 + 4x + -4x

Combine like terms: 4x + -4x = 0
6 + -1x = -2 + 0
6 + -1x = -2

Add '-6' to each side of the equation.
6 + -6 + -1x = -2 + -6

Combine like terms: 6 + -6 = 0
0 + -1x = -2 + -6
-1x = -2 + -6

Combine like terms: -2 + -6 = -8
-1x = -8

Divide each side by '-1'.
x = 8

Simplifying
x = 8